What are the equations of motion that describe a charged particle moving around an oppositely charged pole?
		To simplify further analysis it is convenient to convert to these prolate spheriodal coordinates `(mu,nu,varphi)`: 
            `x = a sinh mu sin nu cos varphi` 
            `y = a sinh mu sin nu sin varphi` 
            `z = a cosh mu cos nu` 
		Also note that: 
			`r = a sinh mu sin nu` 
		For simplicity also define `k` as: 
			`k = (k_e q Q)/(2a)`
    
		Substituting these values in gives: 
        `U(mu,nu) = k ln(( a cosh mu - a cos nu - (a cosh mu cos nu-a)) / (a cosh mu + a cos nu - (a cosh mu cos nu+a)))` 
        `U(mu) = k ln( cosh mu + 1 ) - k ln( cosh mu - 1 ))` 
    
		For the analysis we require a term for kinetic energy, which requires velocity.
        Let `u = sinh mu sin nu`. `dot x` and `dot y` are:  
            `dot x = -a dot varphi u sin varphi + a dot u cos varphi` 
            `dot y =  a dot varphi u cos varphi + a dot u sin varphi` 
        From this it can be seen: 
            `dot x^2 + dot y^2 = a^2 dot varphi^2 u^2 + a^2 dot u^2` 
        Now: 
            `dot u = dot nu sinh mu cos nu + dot mu cosh mu sin nu`  
            `dot z = -a dot nu cosh mu sin nu + a dot mu sinh mu cos nu` 
        From these we can see: 
            `a^2 dot u^2 + dot z^2
                = a^2 (dot mu^2 + dot nu^2) (sinh^2 mu cos^2 nu + cosh^2 mu sin^2 nu)` 
            `   = a^2 (dot mu^2 + dot nu^2) (sinh^2 mu + sin^2 nu)` 
        Now we get: 
            `v^2 = dot x^2 + dot y^2 + dot z^2 =
                a^2 dot varphi^2 sinh^2 mu sin^2 nu
                + a^2 (dot mu^2 + dot nu^2) (sinh^2 mu + sin^2 nu)` 
	
		The Lagrangian is: 
            `cc L(mu,dot mu,nu,dot nu,dot varphi) 
			 = KE - PE` 
            `= 1/2 m v^2  - U(mu)` 
			`= 1/2m [ a^2 dot varphi^2 sinh^2 mu sin^2 nu
                + a^2 (dot mu^2 + dot nu^2) (sinh^2 mu + sin^2 nu)  ]  - U(mu)`
	
        The conjugate momentum to `varphi` is the constant: 
            `p_varphi = (del cc L)/(del dot varphi) = m a^2 dot varphi sinh^2 mu sin^2 nu` 
		Note that `m a^2 dot varphi sinh^2 mu sin^2 nu = m r^2 dot phi` which is the angular
		momentum, so angular momentum in the system is conserved.
    
		In order to derive the equations of motion it is possible to create a Routhian equation, from this
		generate Euler-Lagrange equations, and then with some difficulty integrate them. Curiously all this activity
		leads one around in a circle back to `E = KE + PE` in a form which we can construct without going to
		any of this effort.  
            `E = 
			(m a^2)/2 (dot mu^2 + dot nu^2)(sinh^2 mu + sin^2 nu)
            + p_varphi^2 / (2 m a^2 sinh^2 mu sin^2 nu) 
			- 2k ln[tanh(mu/2)]` 
		In the potential energy portion of the equation `ln [tanh(mu/2)] = -1/2 ln((cosh(mu)+1)/(cosh(mu)-1))` which gives
		the potential energy as calculated above. The kinetic energy portion of the equation has been rearranged
		to remove `dot varphi`.
	
		`dot mu^2 + dot nu^2` is a interesting part of this equation - it is a major component of the velocity and because the total
		energy is constant it is dependant on just two of the position coordinates `mu` and `nu`. It is a convenient 
		quantity to check in simulations.  There is also a shorter form of the energy equation:
            `E = 
			(m a^2)/2 (dot mu^2 + dot nu^2)(sinh^2 mu + sin^2 nu)
			+ 1/2 p_varphi dot phi
			- 2k ln[tanh(mu/2)]` 
		The brevity comes at the expense of adding an extra variable.
	
		It's possible/probable that the energy equation in one of the forms shown above together with the conjugate moment equation 
            ` p_varphi = m a^2 dot varphi sinh^2 mu sin^2 nu` 
		form the best description of the equations of motion of the system.
	
Ideally I would have parametric descriptions of the motion, but this may not be achievable.